I would really appreciate it if someone could draw this out and maybe email it to me qtkoala143@yahoo.com I will definately give you best answer. I can do the trig, it's asking you to find the area, but I just can't seem to figure out how this problem is set up. I don't think I'm doing it right. Or if you could explain how it's set up, that would be okay to. I think what's confusing me is where Burnham road is
From the southeast corner of the cemetary on burnham road, proceed S78W for 250 m along the southern boundary of the cemetery until a granite post is reached, then S15E for 180 m to Allard Road, then N78E along Allard road until it interescts with Burnham Road, and finally N30E along burnham road back to the starting point.
Burnham road is not a N-S road, it actually runs 30 degrees east of north. If you call the starting point A in the upper right corner of the quadrilateral and continue along with my explanation counter-clockwise to vertices B, C and D, here's what I get:
A quadrilateral with angles at the following:
A: 60
B: 87
C: 93
D: 120
and AB = 250 and BC = 180. Since you said you can do the trig once you have the diagram, I didn't continue with the rest of the calculations, but as I was following the directions, when I saw angle B was 87 and angle C was 93 (same side interior angles supplementary, remember that theorem from geometry class?), it told me that AB is parallel to CD, so you have a trapezoid.
US $1,500.00
